If `a=1+b+b^2+b^3+…..to oo where |b|lt1` then roots of equation `ax^2+x-ab=0` are (A) `-1,ab` (B) `1,b` (C) `-1, b` (D) `-1,a`

If a and b are roots of the equation x^2+a x+b=0 , then a+b= (a) 1 (b) 2 (c) -2 (d) -1

If a lt c lt b then the roots of the equation (a−b)x^2 +2(a+b−2c)x+1=0 are

If c lt a lt b lt d , then roots of the equation bx^(2)+(1-b(c+d)x+bcd-a=0

If alpha,beta are the roots of the equation a x^2+b x+c=0 , then 1/(aalpha+b)+1/(abeta+b)= (a) c/(ab) (b) a/(bc) (c) b/(ac) (d) none of these

if a lt c lt b, then check the nature of roots of the equation (a -b)^(2) x^(2) + 2(a+ b - 2c)x + 1 = 0

if a lt c lt b, then check the nature of roots of the equation (a -b)^(2) x^(2) + 2(a+ b - 2c)x + 1 = 0

If a , b ,c real in G.P., then the roots of the equation a x^2+b x+c=0 are in the ratio a. 1/2(-1+isqrt(3)) b. 1/2(1-isqrt(3)) c 1/2(-1-isqrt(3)) d. 1/2(1+isqrt(3))

If a/b+b/a=\ -1, then a^3-b^3=? (a)1 (b) -1 (c) 1/2 (d) 0

If a/b+b/a=1, then a^3+b^3=? (a) 1 (b) -1 (c) 1/2 (d) 0

If the roots of the equation a(b-c)x^2+b(c-a)x+c(a-b)=0 are equal, show that 2//b=1//a+1//cdot