An AP, GP , HP have same first and last term and same odd number of terms .middle term of three series are in

An A.P., and a H.P. have the same first and last terms and the same odd number of terms. The middle terms of the three series are in

an A.P. a G.P. and a H.P. have the same first term & the same last term and the same odd numberof terms . Middle terms of 3 series are in

If an A.P., a G.P. and a H.P. have the same first term and same (2n+1) th term and their (n+1)^n terms are a,b,c respectively, then the radius of the circle. x^2+y^2+2bx+2ky+ac=0 is

A G.P. has first term a=3 , last term l=96 and sum of n terms S=189 . Find the number of terms in it.

Let an A.P. a G.P. and a H.P. of positive terms have the same first term a, the same last term b and the same numberof terms (2n+1). Let x,y,z be the (n+1)th terms respectively of the A.P., G.P. and H.P. respectively. On the basis of above information anwer the following question: x,y,z are in (A) A.P. (B) G.P. (C) H.P. (D) none of these

An A.P. and a G.P. of positive terms have the same first term and the sum of their first, second and third terms are respectively, 1, 1/2 and 2. Show that the sum of their fourth terms is 19/2

If S_1 is the sum of an AP of 'n' odd number of terms and S_2 be the sum of the terms of series in odd places of the same AP then S_1/S_2 =

If S_1 is the sum of an AP of 'n' odd number of terms and S_2 be the sum of the terms of series in odd places of the same AP then S_1/S_2 =

If S_1 is the sum of an AP of 'n' odd number of terms and S_2 be the sum of the terms of series in odd places of the same AP then S_1/S_2 =

The sum of four consecutive numbers in A.P. is 32 and the ratio of the product of the first and last term to the product of two middle terms is 7:15. Find the number