If the sum of the first ten terms of the series `(1(3)/(5))^(2)+(2(2)/(5))^(2)+(3(1)/(5))^(2)+4^(2)+(4(4)/(5))^(2)+"........."" is "(16)/(5)m`, then m equal to

If the sum of the first ten terms of the series (1 3/5)^2+(2 2/5)^2+(3 1/5)^2+4^2+(4 4/5)^2+. . . . . , is (16)/5 m, then m is equal to: (1) 102 (2) 101 (3) 100 (4) 99

If the surm of the first ten terms of the series, (1 3/5)^2+(2 2/5)^2+(3 1/5)^2+4^2+(4 4/5)^2+........ , is 16/5m ,then m is equal to

The sum of the first 10 terms of the series (5)/(1.2.3)+(7)/(2.3.9)+(9)/(3.4.27)+….. is

Sum to n terms of the series 1^(3) - (1.5)^(3) +2^(3)-(2.5)^(3) +…. is

Sum of the n terms of the series (3)/(1^(2))+(5)/(1^(2)+2^(2))+(7)/(1^(2)+2^(2)+3^(3))+"......." is

Sum up to n terms the series 1-(2)/(5)+(3)/(5^(2))-(4)/(5^(3)) + ...

The n ^(th) terms of the series 1 + (4)/(5) + (7)/(5 ^(2)) + (10)/(5 ^(3)) +………. is

Sum of n terms of the series (2n-1)+2(2n-3)+3(2n-5)+... is

Find the sum of n terms of the series 1+4/5+7/(5^2)+10/5^3+......

Find the sum to n terms of the series: 3/(1^2 .2^2)+5/(2^2 .3^2)+7/(3^2 .4^2)+......