If `A (1, 5), B (-2, 1) and C (4, 1)` be the vertices of `DeltaABC` and internal bisector of `/_A` meets `BC` at `D`, find `AD`.

If A ( 2,2,-3) B ( 5,6,9) ,C (2,7,9) be the vertices of a triangle. The internal bisector of the angle A meets BC at the point D, then find the coordinates of D.

A (5, 4), B (-3, -2) and C (1, -8) are the vertices of a triangle ABC. Find : the slope of the median AD .

Let A (4, 2), B(6, 5) and C(1, 4) be the vertices of Delta A B C . (i) The median from A meets BC at D. Find the coordinates of the point D. (ii) Find the coordinates of the point P on AD such that AP : PD = 2 : 1 (iii) Find the coordinates of points Q and R on medians BE and CF respectively such that BQ : QE = 2 : 1 and CR : RF = 2 : 1.

If A(1, 4), B(2, -3) and C (-1, -2) are the vertices of a DeltaABC . Find (i) the equation of the median through A (ii) the equation of the altitude through A. (iii) the right bisector of the side BC .

Let A(1, 2, 3), B(0, 0, 1) and C(-1, 1, 1) are the vertices of triangleABC . Q. The equation of internal angle bisector through A to side BC is

A(1,3)and c(-2/5,-2/5) are the vertices of a DeltaABCand the equation of the angle bisector of /_ABC is x+y=2. find the equation of 'BC'

The points A(4, 5, 10), B(2, 3, 4) and C(1, 2, -1) are three vertices of a parallelogram ABCD. Find the vector equations of side AB and BC and also find the coordinates of point D .

The points A(4, 5, 10), B(2, 3, 4) and C (1, 2,-1) are three vertices of a parallelogram ABCD. Find the vector equations of the sides AB and BC and also find the coordinates of point D.

The points A(4, 5, 10), B(2, 3, 4) and C (1, 2,-1) are three vertices of a parallelogram ABCD. Find the vector equations of the sides AB and BC and also find the coordinates of point D.

A(1,2,3),B(0,4,1),C(-1,-1,-3) are vertices of triangle ABC, find the point at which the bisector of angleBAC meets BC.