One end of a diameterof a circle is at `(2, 3)` and the centre is `(-2, 5)`, find the coordinates of the other end of the diameter.

If one end of a diameter of the circle x^(2) + y^(2) -4x-6y +11=0 is (3, 4), then find the coordinates of the other end of the diameter.

The coordinates of one end of a diameter of a circle are (5, -7) . If the coordinates of the centre be (7, 3) find the coordinates of the other end of the diameter.

If the coordinates of one end of a diameter of a circle are (2,\ 3) and the coordinates of its centre are (-2,\ 5) , then the coordinates of the other end of the diameter are (a) (-6,\ 7) (b) (6,\ -7) (c) (6,\ 7) (d) (-6,\ -7)

If one end of a diameter of the circle x^(2) + y^(2) - 4x - 6y + 11 = 0 is (3, 4), then the coordinates of the other end of the diameter are

If (4, 1) be an end of a diameter of the circle x^2 + y^2 - 2x + 6y-15=0 , find the coordinates of the other end of the diameter.

AB is a diameter of a circle with centre C = (-2, 5). If A = (3, -7). Find the coordinates of B.

One end of the diameter of a circle is (-2, 5). Find the co-ordinates of the other end of it, if the centre of the circle is (2, -1).

The co-ordinates of the end points of a diameter of a circle are (3, -2) and (-3, 6). Find the co-ordinates of the centre and radius.

The equation (x - 7)^(2) + (y - 8)^(2) = 10 is that of a circle that lies in the standard (x,y) coordinate plane. One endpoint of a diameter of the circle has y-coordinate 11. What is the y-coordinate of the other endpoint of that diameter?

If (2, 3, 5) is one end of a diameter of the sphere x^(2)+y^(2)+z^(2)-6x-12y-2z+20=0 , then the coordinates of the other end of the diameter are