The coordinates of centroid of a triangle are `(sqrt(3), 2)` and two of its vertices are `(2sqrt(3), -1) and (2sqrt(3), 5)`. Find the third vertex of the triangle.

The coordinates of the centroid of a triangle and those of two of its vertices are respectively (2/3, 2), (2, 3), (-1, 2) . Find the area of the triangle.

Two vertices of an equilateral triangle are (0, 0) and (0,2 sqrt(3)) . Find the third vertex

The centroid of the triangle with vertices (1, sqrt(3)), (0, 0) and (2, 0) is

The area of a triangle is 5 sq. units. Two. Of its vertices are (2,1) and (3,-2). If the third vertex is ((7)/(2),y), find the value of y.

The area of a triangle is 5. Two of its vertices are (2,\ 1) and (3,\ -2) . The third vertex lies on y=x+3 . Find the third vertex.

Find the third vertex of a triangle, if two of its vertices are at (-3,\ 1) and (0,\ -2) and the centroid is at the origin.

Write the coordinates of third vertex of a triangle having centroid at the origin and two vertices at (3,-5, 7) and (3,0,1).

The area of a triangle is 3 square units. Two of its vertices are A (3, 1), B (1, -3) and the third vertex of the triangle lies on x-axis. Find the coordinates of the third vertex C .

The area of a triangle is 3/2 square units. Two of its vertices are the points A (2, -3) and B(3,-2) , the third vertex of the triangle lies on the line 3x - y -2 = 0 , then third vertex C is

The area of a triangle is 5. Two of its vertices are A(2,1) and B(3,-2) . The third vertex C is on y=x+3. Find Cdot