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The vertices of a DeltaABC are A(3, 0), ...

The vertices of a `DeltaABC` are `A(3, 0), B (0, 6) and C (6, 9)`. A straight line DE divides AB and AC in the ration 1:2 at D and E respectively, prove that `(DeltaABC)/(DeltaADE) = 9`

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