The equation of the locus of points equidistant from (-1, -1) and (4, 2) is

If the equation of the locus of a point equidistant from the points (a_1,b_1) and (a_2,b_2) is (a_1-a_2)x+(b_2+b_2)y+c=0 , then the value of C is

Derive the equation of the locur of a point equidistant from the points (1, -2, 3) and (-3,4,2).

If the equation of the locus of a point equidistant from the points (a_1, b_1) and (a_2, b_2) is (a_1-a_2)x+(b_1-b_2)y+c=0 , then find the value of c .

Find the equation to the locus of a point equidistant from the points A(1,3)a n dB(-2,1)dot

Find the equation to the locus of points equidistant from the points (-3,2),(0,4)

Find the equation to the locus of points equidistant from the points (a + b,a - b),(a - b,a + b)

Find the equation of the set of all points equidistant form the point (4, 2) and the X-axis.

Find the locus of a point which is equidistant from (1,3) and x-axis.

The point on the axis of y which its equidistant from (-1, 2) and (3, 4), is

Find the equation of locus of point equidistant from the points (a_(1)b_(1)) and (a_(2),b_(2)) .