`A (2, 3)` is a fixed point and `Q(3 cos theta, 2 sin theta)` a variable point. If `P` divides `AQ` internally in the ratio 3:1, find the locus of P.

Solve : cos p theta = sin q theta.

The line joining (5, 0) to (10 cos theta, 10 sin theta ) is divided internally in the ratio 2 : 3 at P. the locus of P is

The line joining (5,0) to (10cos theta,10sin theta) is divided internally in the ratio 2:3 at P then the locus of P is

A variable line through the point ((6)/(5),(6)/(5)) cuts the coordinate axes at the points A and B respectively. If the point P divides AB internally in the ratio 2:1 , then the equation of the locus of P is

A variable line through the point (6/5, 6/5) cuts the coordinates axes in the point A and B . If the point P divides AB internally in the ratio 2:1 , show that the equation to the locus of P is :

The locus of the point (2+3cos theta, 1+3 sin theta) when theta is parameter is

Find the coordinates of a point which divides internally the points (1,3,7),(6,3,2) in the ratio 2:3.

If the distance from P to the points (5,-4) (7,6) are in the ratio 2 :3 , then find the locus of P.

If point P(3,2) divides the line segment AB internally in the ratio of 3:2 and point Q(-2,3) divides AB externally in the ratio 4:3 then find the coordinates of points A and B.

If the coordinates of a variable point be (cos theta + sin theta, sin theta - cos theta) , where theta is the parameter, then the locus of P is