Transform equation `sqrt(3) y-3x=3` to the slope intercept form and also find the angle which straight line makes with the x-axis.

Put the equation x/a+y/b=1 to the slope intercept form and find its slope and y-intercept

Reduce x+sqrt3 y+4 =0 to the : Slope intercepts form and find its slope and y-intercept.

Reduce x+sqrt3 y+4 =0 to the : Slope intercepts form and find its slope and y-intercept.

Transform the equation of the line sqrt(3)x+y-8=0 to (i) slope intercept form and find its slope and y-intercept (ii) intercept form and find intercepts in the coordinates axes (iii) normal form and find the inclination of the perpendicular segment from the origin on the line with the axis and its length.

Reduce the equation 3x-2y+6=0 to the intercept form and find the x\ a n d\ y\ intercepts.

For the straight line sqrt(3) y-3x=3 , find the intercepts on the x-axis and y-axis.

Reduce the equation sqrt(3)x+y+2=0 to: (a) Slope intercept form and find slope and y-intercept. (b) Intercept form and find intercept on the axes (c) The normal form and find p\ a n d\ alpha

Find the slope and y-intercept of the line : 3x - 4y = 5

The equation of the line which cuts of intercept 4 on x-ais and makes an angle of 60^(@) with the positive direction of the x-axis is (i) y=sqrt(3)(x+4) (ii) y=-sqrt(3)(x-4) (iii) y=sqrt(3)(x-4) (iv) y=-sqrt(3)(x+4)

Find the slope and the y-intercept of the lines. 3x+2y =6 .