The equations of perpendicular bisectors o the sides AB and AC of a triangle ABC are `x-y+5=0\ a n d\ x+2y=0` respectively. If the point `A\ i s\ (1,-2),` find the equation of the line `B Cdot`

The equations of the perpendicular bisectors of the sides A Ba n dA C of triangle A B C are x-y+5=0 and x+2y=0 , respectively. If the point A is (1,-2) , then find the equation of the line B Cdot

The equations of the perpendicular bisectors of the sides A Ba n dA C of triangle A B C are x-y+5=0 and x+2y=0 , respectively. If the point A is (1,-2) , then find the equation of the line B Cdot

The equation of perpendicular bisectors of side AB,BC of triangle ABC are x-y=5 , x+2y=0 respectively and A(1,-2) then coordinate of C

The equation of perpendicular bisectors of the side AB and AC of a triangle ABC are x-y+5=0 and x+2y=0 respectively vertex A is (1,-2) Area of triangle A B C is (in sq. units) (A) (36)/5 (B) (18)/5 (C) (72)/5 (D) None of these

Perpendicular bisectors of the sides AB and AC of a triangle ABC meet at O. What do you call the point ?

The equation of perpendicular bisectors of the side AB and AC of a triangle ABC are x-y+5=0 and x+2y=0 respectively vertex A is (1,-2) Area of Delta A B C is (a) (36)/5 (b) (18)/5 (c) (72)/5 (d) None of these

The sides AB and AD of a parallelogram ABCD are 2x-y+1=0 and x+3y-10=0 respectively and C is the point (-1, -2) . Find the equation of the diagonals AC.

The sides A Ba n dA C of a triangle A B C are respectively 2x+3y=29a n dx+2y=16 respectively. If the mid-point of B Ci s(5,6) then find the equation of B Cdot

Let the equations of perpendicular bisectors of sides AC and AB of Delta ABC is x + y=3 and x - y=1 respectively Then vertex A is is (0,0) The circumcentre of the DeltaABC is

Let the equations of perpendicular bisectors of sides AC and AB of /_\ ABC be x+y=3 and x-y=1 respectively. Then vertex A is is (0,0). Length of side BC of the DeltaABC is