Altitudes the perpendiculars drawn from the vertices of a triangle to the opposite side are known as the altitudes of the triangle.

Prove that the perpendicular let fall from the vertices of a triangle to the opposite sides are concurrent.

If the altitudes from two vertices of a triangle to the opposite sides are equal, prove that the triangle is isosceles.

If the altitudes from two vertices of a triangle to the opposite sides are equal, prove that the triangle is isosceles.

If A B C is an isosceles triangle with A B=A C . Prove that the perpendiculars from the vertices B and C to their opposite sides are equal.

If A B C is an isosceles triangle with A B=A Cdot Prove that the perpendiculars from the vertices B\ a n d\ C to their opposite sides are equal.

A perpendicular drawn from a vertex to the opposite side of a triangle is known as (a) an altitude (b) a median (c) an angle bisector (d) a bisector

Let the lengths of the altitudes drawn from the vertices of Delta ABC to the opposite sides are 2, 2 and 3. If the area of Delta ABC " is " Delta , then find the area of triangle

An altitutde of a triangle is five –thirds the length of its corresponding base. If the altitude were increased by 4 cm and the base be decreased by 2 cm, the area of the triangle would remain the same. Find the base and the altitude of the triangle.

If area of a triangle is 2 sq. units, then find the value of the product of the arithmetic mean of the lengths of the sides of a triangle and harmonic mean of the lengths of the altitudes of the triangle.

If area of a triangle is 2 sq. units, then find the value of the product of the arithmetic mean of the lengths of the sides of a triangle and harmonic mean of the lengths of the altitudes of the triangle.