Find the equation of the straight line through `(a cos theta, b sin theta)` perpendicular to the line `x/(a cos theta)+ y/(b sin theta) = 1`.

The equation to the straight line passing through the point (a "cos"^(3) theta, a "sin"^(3) theta) and perpendicular to the line x "sec" theta + y"cosec" theta = a is

What is the equation of the plane which passes through the z-axis and is perpendicular to the line (x-a)/(cos theta) = (y+2)/(sin theta) = (z-3)/0 ? (A) x+y tan theta=0 (B) y+x tan theta=0 (C) x cos theta-y sin theta=0 (D) x sin theta-y cos theta=0

Equation of the line passing through the point (acos^3theta, a sin^3theta) and perpendicular to the line xsectheta + y cosec theta =a is xcostheta-ysintheta =acos2theta .

If x cos theta + y sin theta =2 is perpendicular to the line x-y =3 then what is one of the value of theta ?

if a cos theta + b sin theta = c. then what is the value of a sin theta -b cos theta

Eliminate theta from a sin theta + bcos theta = x "and" a cos theta -b sin theta = y

If a cos theta-b sin theta = c, then find the value of a sin theta + b cos theta.

Find the equation of normal to the curve x = a cos^(3)theta, y=b sin^(3) theta" at point "'theta'.

The line passing through (-1,pi/2) and perpendicular to sqrt3 sin(theta) + 2 cos (theta) = 4/r is

The area of the triangle with vertices (a, 0), (a cos theta, b sin theta), (a cos theta, -b sin theta) is