I the equations of two diameters of a circles are `2x+y=6\ a n d\ 3x+2y=4` and the radius is 10, find the equation of the circle.

If the equations of two diameters of a circles are x+y=6\ a n d\ x+2y=4 and the radius is 10, find the equation of the circle.

If the equations of the two diameters of a circle are x-y=5\ and \ 2x+y=4 and the radius of the circle is 5, find the equation of the circle.

The equation of two diameters of a cirlce are x - y = 5 and 2 x + y = 4 and the radius of the circle is 5, then the equation of t he circle is

The equations of two sides of a triangle are 3x-2y+6=0\ a n d\ 4x+5y-20\ a n d\ the orthocentre is (1,1). Find the equation of the third side.

The equation of diameter of a circle passing through origin is x+y=1 and the greatest distance of any point of the circle from the diameter is sqrt(5) , then an equation of the circle is: (A) x^2+y^2-2x+4y=0 (B) x^2+y^2-4x+2y=0 (C) x^2+y^2+2x-2y=0 (D) none of these

Find the equation of a circle, the equation of whose two diameters are x + y = 6 and 3x +4y =16 and radius is 10.

If the lines 2x-3y=5 and 3x-4y=7 are the diameters of a circle of area 154 square units, then obtain the equation of the circle.

(i) Find the equation of a circle concentric with the circle x^(2)+y^(2)-8x+6y-10=0 and passes through the point (-2,3). (ii) Find the equation of circle concentric with the circle x^(2)+y^(2)-4x-8y-6=0 and whose radius is three times the radius of this circle.

The equation of radical axis of two circles is x + y = 1 . One of the circles has the ends ofa diameter at the points (1, -3) and (4, 1) and the other passes through the point (1, 2).Find the equations of these circles.

If the lines 3x-4y-7 = 0 and 2x-3y-5=0 are two diameters of a circle of area 49pi square units, the equation of the circle is: