ABC is a triangle whose medians AD and BE are perpendicular to each other. If `AD=p` and `BE = q` then area of `triangleABC` is

In a triangle ABC, medians AD and CE are drawn. If AD=5, angle DAC=pi/8 and angle ACE=pi/4 then the area of the triangle ABC is equal to (5a)/b, then a+b is equal to

In a Delta ABC , the median AD is perpendicular to AC. If b = 5 and c = 11, then a =

In triangle ABC medians AD and CE are drawn, if AD=5, angleDAC= pi/8 and angleACE=pi/4 , then the area of triangle ABC is equal to a. 25/8 b. 25/3 c. 25/18 d. 10/3

In a triangle ABC, medians AD and BE are deawn. IF AD= 4, angle D AB=(pi)/(6) and angle ABE=(pi)/(3), then the area of the trianlge ABC is-

In a DeltaABC, if median AD is perpendicular to AB, the tan A+2 tan B is equal to

The following figure shows a triangle ABC in which AD and BE are perpendiculars to BC and AC respectively. Show that : Delta ADC ~ DeltaBEC

Delta ABC is right angled at A (Fig 11.25 ). AD is perpendicular to BC. If AB=5cm, BC=13 and, find the area of DeltaABC Also find the lenght of AD.

The following figure shows a triangle ABC in which AD and BE are perpendiculars to BC and AC respectively. Show that : DeltaABC ~ DeltaDEC

ABC is a triangle. D is the middle point of BC. If AD is perpendicular to AC, The value of cos A cos C , is

let ABC be a right angled triangle at C. If the inscribed circle touches the side AB at D and (AD) (BD)=11, then find the area of triangle ABC. .