If `(alpha,alpha^2)` lies inside the triangle formed by the lines `2x+3y-1=0,x+2y-3=0,5x-6y-1=0` , then `2alpha+3alpha^2-1>0` `alpha+2alpha^2-3<0` `alpha+2alpha^2-3<0` (d) `6alpha^2-5a+1>0`

If point P(alpha, alpha^2-2) lies inside the triangle formed by the lines x + y=1 , y=x + 1 and y=-1 then alpha in

If the point (alpha, alpha^(4)) lies on or inside the triangle formed by lines x^(2)y+xy^(2)-2xy=0 , then the largest value of alpha is .

Statement 1: The value of alpha for which the point (alpha,alpha^2) lies inside the triangle formed by the lines x=0,x+y=2 and 3y=x is (0,1)dot Statement 2: The parabola y=x^2 meets the line x+y=2 at (1,1)dot

Determine all the values of alpha for which the point (alpha,alpha^2) lies inside the triangle formed by the lines. 2x+3y-1=0 x+2y-3=0 5x-6y-1=0

Determine all the values of alpha for which the point (alpha,alpha^2) lies inside the triangle formed by the lines. 2x+3y-1=0 x+2y-3=0 5x-6y-1=0

The range of value of alpha such that (0,alpha) lies on or inside the triangle formed by the lines y + 3x + 2 = 0, 3y - 2x - 5 = 0, 4y + x - 14 =0 is

If the point (1, alpha) always remains in the interior of the triangle formed by the lines y = x, y = 0 and x + y = 4, then alpha lies in the interval

Find the values of alpha so that the point P(alpha^2,alpha) lies inside or on the triangle formed by the lines x-5y+6=0,x-3y+2=0 a n d x-2y-3=0.

Find the values of alpha so that the point P(alpha^2,alpha) lies inside or on the triangle formed by the lines x-5y+6=0,x-3y+2=0a n dx-2y-3=0.

The point P(alpha,alpha +1) will lie inside the triangle whose vertices are A(0,3), B(-2,0) and C(6,1) if