A straight line through the point A `(-2,-3)` cuts the line `x+3y=0` and `x+y+1=0` at B and C respectively. If AB.AC`=20` then equation of the possible line is

A straight line through the point A (-2,-3) cuts the line x+3y=9 and x+y+1=0 at B and C respectively. If AB.AC =20 then equation of the possible line is

A straight line through the point (2,2) intersects the lines sqrt(3)x+y=0 and sqrt(3)x-y=0 at the point A and B , respectively. Then find the equation of the line A B so that triangle O A B is equilateral.

A straight line through the point (2,2) intersects the lines sqrt(3)x+y=0 and sqrt(3)x-y=0 at the point A and B , respectively. Then find the equation of the line A B so that triangle O A B is equilateral.

A straight line through origin O meets the lines 3y=10-4x and 8x+6y+5=0 at point A and B respectively. Then , O divides the Segment AB in the ratio.

A straight line through A (-15 -10) meets the lines x-y-1=0 , x+2y=5 and x+3y=7 respectively at A, B and C. If 12/(AB)+40/(AC)=52/(AD) prove that the line passes through the origin.

A line passes through the point of intersection of the line 3x+y+1=0 and 2x-y+3=0 and makes equal intercepts with axes. Then, equation of the line is

A Line through the variable point A(1+k;2k) meets the lines 7x+y-16=0; 5x-y-8=0 and x-5y+8=0 at B;C;D respectively. Prove that AC;AB and AD are in HP.

The straight line passing through the point of intersection of the straight line x+2y-10=0 and 2x+y+5=0 is

Find the equation of the straight line drawn through the point of intersection of the lines x+y=4\ a n d\ 2x-3y=1 and perpendicular to the line cutting off intercepts 5,6 on the axes.

Find the equation of the straight line passing through the point of intersection of the two line x+2y+3=0 and 3x+4y+7=0 and parallel to the straight line y-x=8