Home
Class 12
MATHS
The normal form of the eqatuion of the l...

The normal form of the eqatuion of the line `x+sqrt(3y) = 4` is (A) `x cos 60^0 + y sin 60^0 = 2` (B) `x cos 24^0 - y sin 24^0 - 2` (C) `x cos 240^0 + y sin 240^0 - 2` (D) none of these

Promotional Banner

Similar Questions

Explore conceptually related problems

Number of solutions of the equation sin x + cos x-2sqrt(2) sin x cos x=0 for x in [0, pi] is

The normal at the point (1,1) on the curve 2y+x^2=3 is (A) x - y = 0 (B) x y = 0 (C) x + y +1 = 0 (D) x y = 0

The normal at the point (1,1) on the curve 2y+x^2=3 is (A) x + y = 0 (B) x y = 0 (C) x + y +1 = 0 (D) x y = 0

The roots of the equation 4x^2-2sqrt(5)x+1=0,a r e (a) sin36^0,sin18^0 (b) sin18^0,cos36^0 (c) sin36^0,cos18^0 (d) cos18^0,cos36^0

The angle between the plane 3x+4y=0 and the line x^2+y^2=0 is (A) 0^0 (B) 30^0 (C) 60^0 (D) 90^0

Solve the equation sin x + cos x -2sqrt2 sin x cos x =0

If x e^(x y)-y=sin^2x then (dy)/(dx)a tx=0 is a. 0 b. 1 c. -1 d. none of these

The solution the differential equation "cos x sin y dx" + "sin x cos y dy" =0 is

Prove that: sin780^0sin 120^0+cos 240^0sin390^0=1/2

The angle between the lines 5x+3y-7=0\ a n d\ 15 x+9y+14=0 is a. 0^0 b. 60^0 c. 45^0 d. 30^0