The incident ray is along the line 24x+7y+5=0. Find the equation of mirrors.

The incident ray is along the line 3x-4y-3=0 and the reflected ray is along the line 24 x+7y+5=0. Find the equation of mirrors.

The incident ray is along the line 3x-4y-3=0 and the reflected ray is along the line 24 x+7y+5=0. Find the equation of mirrors.

A ray of light is sent along the line 2x-3y=5. After refracting across the line x+y=1 it enters the opposite side after torning by 15^0 away from the line x+y=1 . Find the equation of the line along which the refracted ray travels.

A ray of light is incident along a line which meets another line, 7x-y+1 = 0 , at the point (0, 1). The ray isthen reflected from this point along the line, y+ 2x=1 . Then the equation of the line of incidence of the ray of light is (A) 41x + 38 y - 38 =0 (B) 41 x - 38 y + 38 = 0 (C) 41x + 25 y - 25 = 0 (D) 41x - 25y + 25 =0

In the figure given the angle between incident ray and the reflected ray is 70^@ Find the angle between the mirror and the incident ray.

The equation of a line is 3x + 4y - 7 = 0 . Find: the equation of a line perpendicular to the given line and passing through the intersection of the lines x - y + 2 = 0 and 3x + y - 10 = 0 .

The refractive index of an anisotropic medium varies as mu=mu_(0)sqrt((x+1)) , where 0lexlea . A ray of light is incident at the origin just along y-axis (shown in figure). Find the equation of ray in the medium .

Fig. shows an incident ray AO and the normal ON on a plane mirror. The angle which the incident ray AO makes with mirror is 30^@ . Find the angle of incidence.

If a ray travelling the line x = 1 gets reflected the line x+y=1 then the equation of the line along which the reflected ray travels is

One side of a rectangle lies along the line 4x+7y+5=0. Two of its vertices are (-3,1)a n d(1,1)dot Find the equations of the other three sides.