The sides of a triangle are the straight line x+y=1, 7y=x, and `sqrt(3)y +x = 0`. Then which of the following is an interior point of the triangle?

The sides of a triangle are the straight lines x+y=1,7y=x , and sqrt(3)y+x=0 . Then which of the following is an interior point of the triangle? (a)Circumcenter (b) Centroid (c)Incenter (d) Orthocenter

The sides of a triangle are the straight lines x+y=1,7y=x , and sqrt(3)y+x=0 . Then which of the following is an interior point of the triangle? Circumcenter (b) Centroid Incenter (d) Orthocenter

The triangle formed by the straight lines x=y , x+y=4 and x+3y=4 is :

The area of triangle formed by the straight lies y=1 , 2x+y=2 and 2x-y+2=0 is ,

Find the area of the triangle formed by the straight lines 7x-2y+10=0, 7x+2y-10=0 and 9x+y+2=0 (without sloving the vertices of the triangle).

Find the area of the triangle formed by the straight lines y=2x, x=0 and y=2 by integration.

The sides of a triangle are given by x-2y+9=0, 3x+y-22=0 and x+5y+2=0 . Find the vertices of the triangle.

A triangle is formed by the straight lines x + 2y - 3 =0 , 3x - 2y + 7 =0 and y+ 1 =0 , find graphically the area of the triangle.

The sides of a triangle are given by the equations 3x+4y=10, 4x-3y=5, and 7x+y+10=0 , show that the origin lies within the triangle.