Show that the circle on the chord `xcosalpha+ ysinalpha-p = 0` of the circle `x^2+ y^2 = a^2` as diameter is `x^2 + y^2 - a^2 - 2p (xcosalpha + ysinalpha-p) = 0.`

If the straight line represented by x cos alpha + y sin alpha = p intersect the circle x^2+y^2=a^2 at the points A and B , then show that the equation of the circle with AB as diameter is (x^2+y^2-a^2)-2p(xcos alpha+y sin alpha-p)=0

If we reduce 3x+3y+7=0 to the form xcosalpha+ysinalpha=p , then find the value of p .

The equation of the circle described on the common chord of the circles x^(2)+y^(2)+2x=0 and x^(2)+y^(2)+2y=0 as diameter, is

The equation of the circle on the common chord of the circles (x-a)^(2)+y^(2)=a^(2) and x^(2)+(y-b)^(2)=b^(2) as diameter, is

The condition that the chord xcosalpha+ysinalpha-p=0 of x^2+y^2-a^2=0 may subtend a right angle at the center of the circle is _

If the straight line xcosalpha+ysinalpha=p touches the curve (x^2)/(a^2)+(y^2)/(b^2)=1 , then prove that a^2cos^2alpha+b^2sin^2alpha=p^2 .

If the straight line xcosalpha+ysinalpha=p touches the curve (x^2)/(a^2)+(y^2)/(b^2)=1 , then prove that a^2\ cos^2alpha+b^2\ sin^2alpha=p^2 .

If the straight line xcosalpha+ysinalpha=p touches the curve (x^2)/(a^2)-(y^2)/(b^2)=1 , then p^2dot

Find the parametric form of the equation of the circle x^2+y^2+p x+p y=0.

Find the parametric form of the equation of the circle x^2+y^2+p x+p y=0.