Two circles have the equations` x^2+y^2+lambdax+c=0 and x^2+y^2+mux+c=0`. Prove that one of the circles will be within the other if `lambdamugt0 and cgt0`.

If one of the circles x^2+y^2+2ax+c=0 and x^2+y^2+2bx+c=0 lies within the other, then

If two circles and a(x^2 +y^2)+bx + cy =0 and p(x^2+y^2)+qx+ry= 0 touch each other, then

The number of common tangents to the circles x^2+y^2-x = 0 and x^2 + y^2 + x = 0 are

If 2x^2+lambdax y^+2y^2+(lambda-4)x+6y-5=0, is the equation of a circle, then its radius is :

The two circles x^(2)+y^(2)-cx=0 and x^(2)+y^(2)=4 touch each other if:

If the circles x^2+y^2+2ax+c=0 and x^2+y^2+2by+c=0 touch each other, then find the relation between a, b and c .

There are two circles whose equation are x^2+y^2=9 and x^2+y^2-8x-6y+n^2=0,n in Zdot If the two circles have exactly two common tangents, then the number of possible values of n is (a)2 (b) 8 (c) 9 (d) none of these

If circles x^(2)+y^(2)+2x+2y+c=0 and x^(2)+y^(2)+2ax+2ay+c=0 where c in R^(+), a != 1 are such that one circle lies inside the other, then

The condition that the circles x^(2)+y^(2)+2ax+c=0, x^(2)+y^(2)+2by+c=0 may touch each other is

The condition that the circles x^(2)+y^(2)+2ax+c=0, x^(2)+y^(2)+2by+c=0 may touch each other is