The equation of three circles are given `x^2+y^2=1,x^2+y^2-8x+15=0,x^2+y^2+10 y+24=0` . Determine the coordinates of the point `P` such that the tangents drawn from it to the circle are equal in length.

The length of the chord of contact of the tangents drawn from the point (-2,3) to the circle x^2+y^2-4x-6y+12=0 is:

The equation of the circle which cuts the three circles x^2+y^2-4x-6y+4=0, x^2+y^2-2x-8y+4=0, x^2+y^2-6x-6y+4=0 orthogonally is

The straight line x-2y+5=0 intersects the circle x^(2)+y^(2)=25 in points P and Q, the coordinates of the point of the intersection of tangents drawn at P and Q to the circle is

Find the equation of tangents of the circle x^(2) + y^(2) - 8 x - 2y + 12 = 0 at the points whose ordinates are -1.

If the straight line x - 2y + 1 = 0 intersects the circle x^2 + y^2 = 25 at points P and Q, then find the coordinates of the point of intersection of the tangents drawn at P and Q to the circle x^2 + y^2 = 25 .

If the straight line x - 2y + 1 = 0 intersects the circle x^2 + y^2 = 25 at points P and Q, then find the coordinates of the point of intersection of the tangents drawn at P and Q to the circle x^2 + y^2 = 25 .

The point of tangency of the circles x^2+ y^2 - 2x-4y = 0 and x^2 + y^2-8y -4 = 0 , is

The point of tangency of the circles x^2+ y^2 - 2x-4y = 0 and x^2 + y^2-8y -4 = 0 , is

The straight line x-2y+1=0 intersects the circle x^(2)+y^(2)=25 in points P and Q the coordinates of the point of intersection of tangents drawn at P and Q to the circle is

The equation of the tangent to the circle x^(2)+y^(2)-4x+4y-2=0 at (1,1) is