The four points of intersection of the lines (2x-y+1)(x-2y+3)=0 with the axes lie on a circle whose centre is at the point

The four point of intersection of the lines ( 2x -y +1) ( x- 2y +3) = 0 with the axes lie on a circle whose center centre is at the point :

Show that the four points of intersection of the lines : (2x-y + 1) (x-2y+3) = 0 , with the axes lie on a circle and find its centre.

Find the point of intersection of the lines 2x-3y+8=0 and 4x+5y=6

Find the point of intersection of the circle x^2+y^2-3x-4y+2=0 with the x-axis.

If the 4 points made by intersection of lines 2x-y+1=0, x-2y+3=0 with the coordinate axes are concylic then centre of circle is

If a circle passes through the points of intersection of the lines 2x-y +1=0 and x+lambda y -3=0 with the axes of reference then the value of lambda is :

The point of intersection of the two lines given by 2x^2-5xy +2y^2-3x+3y+1=0 is

The points of intersection of the parabolas y^(2) = 5x and x^(2) = 5y lie on the line

Find the equation of the circle passing through the point of intersection of the lines x+3y=0\ a n d\ 2x-7y=0 and whose centre is the point of intersection of the lines x+y+1=0\ a n d\ x-2y+4=0.

Find the equation of a line passing through the point of intersection of the lines x+y=4 and 2x-3y-1=0 and parallel to a line whose intercepts on the axes are 4 and 6 units.