The shortest distance between the parabola `y^2 = 4x` and the circle `x^2 + y^2 + 6x - 12y + 20 = 0` is : (A) 0 (B) 1 (C) `4sqrt(2) -5` (D) `4sqrt(2) + 5`

The equation of the line of the shortest distance between the parabola y^(2)=4x and the circle x^(2)+y^(2)-4x-2y+4=0 is

The shortest distance between the parabolas 2y^2=2x-1 and 2x^2=2y-1 is: (a) 2sqrt(2) (b) 1/(2sqrt(2)) (c) 4 (d) sqrt((36)/5)

What is the shortest distance between the circle x^(2)+y^(2)-2x-2y=0 and the line x=4?

Find shortest distance between y^(2) =4x" and "(x-6)^(2) +y^(2) =1

The shortest distance of (-5,4) to the circle x^(2)+y^(2)-6x+4y-12=0 is

Show that the line 5x + 12y - 4 = 0 touches the circle x^(2)+ y^(2) -6x + 4y + 12 = 0

The co-ordinates of the middle point of the chord cut off on 2x - 5y +18= 0 by the circle x^2 + y^2 - 6x + 2y - 54 = 0 are (A) (1,1) (B) (2, 4) (C) (4,1) (D) (1, 4)

The shortest distance between line y-x=1 and curve x=y^2 is (a) (3sqrt2)/8 (b) 8/(3sqrt2) (c) 4/sqrt3 (d) sqrt3/4

The line x-y+2=0 touches the parabola y^2 = 8x at the point (A) (2, -4) (B) (1, 2sqrt(2)) (C) (4, -4 sqrt(2) (D) (2, 4)

The line x-y+2=0 touches the parabola y^2 = 8x at the point (A) (2, -4) (B) (1, 2sqrt(2)) (C) (4, -4 sqrt(2) (D) (2, 4)