Home
Class 12
MATHS
The equation x = (2atheta)/(1+theta^2), ...

The equation `x = (2atheta)/(1+theta^2), y = (a(1-theta^2))/(1+theta^2)` where `a` is constant, is the parametric equation of the curve (A) `x^2 - y^2 = a^2` (B) `x^2 + 4y^2 = 4a^2` (C) `x^2 + y^2 = a^2` (D) `x-2y=a^2`

Text Solution

AI Generated Solution

Promotional Banner

Similar Questions

Explore conceptually related problems

Find the parametric equation of the circles : x^2 + y^2 + 2x - 4y - 1 =0

Find the parametric equation of the circles : x^2 + y^2 - 2x+4y-4=0

The parametric equations of the circle x^(2)+y^(2)+2x+4y-11=0 are

The equation x = t^(2) + 1 and y = 2t + 1 , where t is any real number, are the parametric equation of the parabola (i) y^(2) - 4x - 2y + 5 = 0 (ii) y^(2) + 4x - 2y + 5 = 0 (iii) y^(2) - 4x + 2y + 3 = 0 (iv) y^(2) - 4x - 2y - 5 = 0

Find the equation of the normal to the curve x^2/a^2-y^2/b^2=1 at (x_0,y_0)

The curve with parametric equations x=1 +4cos theta , y= 2 +3 sin theta . is

The equation of common tangent to the curves y^2 =4x and xy=2 is (A) x+2y-4=0 (B) x+2y+4=0 (C) x-2y+4=0 (D) x-2y-4=0

The equation of common tangent to the curves y^2 =4x and xy=2 is (A) x+2y-4=0 (B) x+2y+4=0 (C) x-2y+4=0 (D) x-2y-4=0

The equation of the tangent to the circle x^(2)+y^(2)-4x+4y-2=0 at (1,1) is

Find the equation of the tangent to the curve (x^2)/(a^2)+(y^2)/(b^2)=1 at (x_1,\ y_1) on it.