If one end of a diameter of the circle `x^2 + y^2 - 8x - 14y+c=0` is the point `(-3, 2)`, then its other end is the point. (A) `(5, 7)` (B) `(9, 11)` (C) `(10, 11)` (D) `(11, 12)`

If one end of a diameter of the circle 2x^(2)+2y^(2)-4x-8y+2=0 is (-1,2), then the other end of the diameter is

If one end of the diameter of the circle 2x^2+2y^2-4x-8y+2=0 is (3,2), then find the other end of the diameter.

If one end of a diameter of the circle x^(2) + y^(2) - 4x - 6y + 11 = 0 is (3, 4), then the coordinates of the other end of the diameter are

If (4, 1) be an end of a diameter of the circle x^2 + y^2 - 2x + 6y-15=0 , find the coordinates of the other end of the diameter.

If one end of a diameter of the circle x^(2) + y^(2) -4x-6y +11=0 is (3, 4), then find the coordinates of the other end of the diameter.

If the coordinate of one end of a diameter of the circle x^2+y^2+4x−8y+5=0 is (2,1), the coordinates of the other end is a) (-6,--7) b) (6,7) c) (-6,7) d) (7,-6)

Find the centre and radius of the circles : 3x^2 + 3y^2 + 12x - 18y - 11=0

If one of the diameters of the curve ""^(2) + y ^(2) - 4x - 6y +9=0 is a chord of a circle with centre (1,1) then the radius of this circel is

Tangent to the curve y=x^2+6 at a point (1,7) touches the circle x^2+y^2+16x+12y+c=0 at a point Q , then the coordinates of Q are (A) (-6,-11) (B) (-9,-13) (C) (-10,-15) (D) (-6,-7)

If (2, 3, 5) is one end of a diameter of the sphere x^(2)+y^(2)+z^(2)-6x-12y-2z+20=0 , then the coordinates of the other end of the diameter are