Home
Class 12
MATHS
The shortest distance from the point (0,...

The shortest distance from the point `(0, 5)` to the circumference of the circle `x^2 + y^2 - 10x + 14y - 151 = 0` is: (A) 13 (B) 9 (C) 2 (D) 5

Text Solution

AI Generated Solution

Promotional Banner

Similar Questions

Explore conceptually related problems

The circumference of circle x^(2)+y^(2)-10y-36=0 is

The shortest distance of the point (8,1) from the circle (x + 2)^(2) + (y - 1)^(2) = 25 is

. The shortest distance from the point (2, -7) to circle x^2+y^2-14x-10y-151=0

The shortest distance of the point (1, 3, 5) from x^(2) + y^(2) = 0 is

The shortest distance between the parabola y^2 = 4x and the circle x^2 + y^2 + 6x - 12y + 20 = 0 is : (A) 0 (B) 1 (C) 4sqrt(2) -5 (D) 4sqrt(2) + 5

The distance of the point (1, 2) from the common chord of the circles x^2+y^2-2x+3y-5=0 and x^2+y^2+10x+8y=1 is

The distance of the point (1,-2) from the common chord of the circles x^(2) + y^(2) - 5x +4y - 2= 0 " and " x^(2) +y^(2) - 2x + 8y + 3 = 0

Find the shortest distance of the point (0, c) from the parabola y=x^2 , where 0lt=clt=5 .

Find the shortest distance of the point (0, c) from the parabola y=x^2 , where 0lt=clt=5 .

Find the shortest distance of the point (0, c) from the parabola y=x^2 , where 0lt=clt=5 .