The equation of the diameter of the circle `x^2 + y^2 + 4x + 4y-11=0`, which bisects the chord cut off by the circle on the line `2x-3y-3=0` is `3x+2y+10=0`. Statement 2 : The diameter of a circle is a chord of the circle of maximum length. (A) Both 1 and 2 are true and 2 is the correct explanation of 1 (B) Both 1 and 2 are true and 2 is not a correct explanation of 1 (C) 1 is true but 2 is false (D) 1 is false but 2 is true

Statement 1 : The circle x^2 + y^2 - 8x - 6y + 16=0 touches x-axis. Statement : 2 : y-coordinate of the centre of the circle x^2 + y^2 - 8x -6y+16=0 is numerically equal to its radius. (A) Both 1 and 2 are true and 2 is the correct explanation of 1 (B) Both 1 and 2 are true and 2 is not a correct explanation of 1 (C) 1 is true but 2 is false (D) 1 is false but 2 is true

Equation of the diameter of the circle x^(2) +y^(2) - 2x + 4y = 0 which passes through the origin is

The equation of the tangent to the circle x^(2)+y^(2)-4x+4y-2=0 at (1,1) is

x-y+b=0 is a chord of the circle x^2 + y^2 = a^2 subtending an angle 60^0 in the major segment of the circle. Statement 1 : b/a = +- sqrt(2) . Statement 2 : The angle subtended by a chord of a circle at the centre is twice the angle subtended by it at any point on the circumference. (A) Both 1 and 2 are true and 2 is the correct explanation of 1 (B) Both 1 and 2 are true and 2 is not a correct explanation of 1 (C) 1 is true but 2 is false (D) 1 is false but 2 is true

The normal of the circle (x- 2)^(2)+ (y- 1)^(2) =16 which bisects the chord cut off by the line x-2y-3=0 is

The line x+3y=0 is a diameter of the circle x^2+y^2-6x+2y=0

The equation of the chord of the circle x^(2)+y^(2)-6x+8y=0 which is bisected at the point (5, -3), is

The equation of the normal to the circle x^(2)+y^(2)+6x+4y-3=0 at (1,-2) to is

Show that the circle x^2+y^2+4x+4y-1=0 bisects the circumference of the circle x^2+y^2+2x-3=0 .

The equation of the chord of the circle x^(2)+y^(2)-4x+6y-3=0 having (1,-2) as it midpoint is