If the loucus of the feet of perpendicular from the foci on any tangent to an ellipse `(x^(2))/(4) + (y^(2))/(2) =1` is `x^(2) + y^(2) =k`, then the value of k is _______.

The locus of the foot of the perpendicular from the foci an any tangent to the ellipse x^(2)/a^(2) + y^(2)/b^(2) = 1 , is

Prove that the product of the perpendicular from the foci on any tangent to the ellips (x^(2))/(a^(2))+(y^(2))/(b^(2)) =1 is equal to b^(2)

Find the locus of the foot of the perpendicular drawn from the center upon any tangent to the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1.

The length of perpendicular from the foci S and S on any tangent to ellipse (x^(2))/(4)+(y^(2))/(9)=1 are a and c respectively then the value of ac is equal to

Prove that the product of the perpendiculars from the foci upon any tangent to the ellipse x^2/a^2+y^2/b^2=1 is b^2

Prove that the product of the perpendiculars from the foci upon any tangent to the ellipse x^2/a^2+y^2/b^2=1 is b^2

If the locus of the foot of the perpendicular drawn from centre upon any tangent to the ellipse (x^(2))/(40)+(y^(2))/(10)=1 is (x^(2)+y^(2))^(2)=ax^(2)+by^(2) , then (a-b) is equal to

Find the locus of the feet of the perpendiculars drawn from the point (b, 0) on tangents to the circle x^(2) + y^(2) =a^(2)

The locus of point intersection of perpendicular tangents of ellipse ((x-1)^(2))/(16)+((y-1)^(2))/(9)=1 is

Find the locus of feet of perpendicular from (5,0) to the tangents of (x^(2))/(16)-y^(2)/(9)=1