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The normal at a point P on the ellipse x...

The normal at a point `P` on the ellipse `x^2+4y^2=16` meets the x-axis at `Qdot` If `M` is the midpoint of the line segment `P Q ,` then the locus of `M` intersects the latus rectums of the given ellipse at points. `(+-((3sqrt(5)))/2+-2/7)` (b) `(+-((3sqrt(5)))/2+-(sqrt(19))/7)` `(+-2sqrt(3),+-1/7)` (d) `(+-2sqrt(3)+-(4sqrt(3))/7)`

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The normal at a point P on the ellipse x^2+4y^2=16 meets the x-axis at Qdot If M is the midpoint of the line segment P Q , then the locus of M intersects the latus rectums of the given ellipse at points. (a) (+-((3sqrt(5)))/2+-2/7) (b) (+-((3sqrt(5)))/2+-(sqrt(19))/7) (c) (+-2sqrt(3),+-1/7) (d) (+-2sqrt(3)+-(4sqrt(3))/7)

(sqrt(7)+2sqrt(3))(sqrt(7)-2sqrt(3))

The eccentricity of the ellipse 4x^2+9y^2=36 is a. 1/(2sqrt(3)) b. 1/(sqrt(3)) c. (sqrt(5))/3 d. (sqrt(5))/6

The eccentricity of the ellipse 4x^2+9y^2=36 is a. 1/(2sqrt(3)) b. 1/(sqrt(3)) c. (sqrt(5))/3 d. (sqrt(5))/6

Find the 5th term of the progression 1,((sqrt(2)-1))/(2sqrt(3)),\ ((3-2sqrt(2))/(12)),\ ((5sqrt(2)-7)/(24sqrt(3))),\ ddot

Factorise: (i) 4sqrt(3)x^(2) + 5x-2sqrt(3) (ii) 7sqrt(2)x^(2)-10x - 4sqrt(2)

The latus rectum of the conic 3x^2+4y^2-6x+8y-5=0 is a. 3 b. (sqrt(3))/2 c. 2/(sqrt(3)) d. none of these

Simplify: (i) (7+3\ sqrt(5))/(3+\ sqrt(5))-(7-3\ sqrt(5))/(3-\ sqrt(5)) (ii) 1/(2+sqrt(3)\ )+2/(sqrt(5)-\ sqrt(3))+1/(2-\ sqrt(5))

The length of latus rectum of the ellipse 3x^(2) + y^(2) = 12 is (i) 4 (ii) 3 (iii) 8 (iv) (4)/(sqrt(3))

Rationalise the denominator in each of the following: (i) 2/(sqrt(7)) (ii) 2/(3sqrt(3)) (iii) (2sqrt(7))/(sqrt(11))