Let P be the point on the parabola `y^2=4x` which is at the shortest distance from the center S of the circle `x^2+y^2−4x−16y+64=0`. Let Q be the point on the circle dividing the line segment SP internally. Then

Let P be the point on parabola y^2=4x which is at the shortest distance from the center S of the circle x^2+y^2-4x-16y+64=0 let Q be the point on the circle dividing the line segment SP internally. Then

. The shortest distance from the point (2, -7) to circle x^2+y^2-14x-10y-151=0

The shortest distance from the line 3x+4y=25 to the circle x^2+y^2=6x-8y is equal to :

Let P be the point on the parabola, y^2=8x which is at a minimum distance from the centre C of the circle, x^2+(y+6)^2=1. Then the equation of the circle, passing through C and having its centre at P is : (1) x^2+y^2-4x+8y+12=0 (2) x^2+y^2-x+4y-12=0 (3) x^2+y^2-x/4+2y-24=0 (4) x^2+y^2-4x+9y+18=0

Find the greatest distance of the point P(10 ,7) from the circle x^2+y^2-4x-2y-20=0

The shortest distance of (-5,4) to the circle x^(2)+y^(2)-6x+4y-12=0 is

What is the shortest distance between the circle x^(2)+y^(2)-2x-2y=0 and the line x=4?

The maximum distance of the point (4,4) from the circle x^2+y^2-2x-15=0 is

The point(s) on the parabola y^2 = 4x which are closest to the circle x^2 + y^2 - 24y + 128 = 0 is/are

The least distance of the line 8x -4y+73=0 from the circle 16x^2+16y^2+48x-8y-43=0 is