Show that the length of the focal chords of ellipse `x^2/a^2 + y^2/b^2 = 1` which makes an angle `theta` with the major axis is ` (2ab^2)/(b^2 cos^2 theta + a^2 sin^2 theta)` unit

Length of the focal chord of the ellipse x^2/a^2+y^2/b^2= 1 which is inclined to the major axis at angle theta is

The length of a focal chord of the parabola y^2=4ax making an angle theta with the axis of the parabola is (a> 0) is :

Find the locus of the points of the intersection of tangents to ellipse x^(2)/a^(2)+y^(2)/b^(2)=1 which make an angle theta.

If the length of the latusrectum of the ellipse x^(2) tan^(2) theta + y^(2) sec^(2) theta = 1 is 1/2, then theta =

If (a+b)^2/(4ab)=sin^2theta , then

If eccentric angle of a point lying in the first quadrant on the ellipse x^2/a^2 + y^2/b^2 = 1 be theta and the line joining the centre to that point makes an angle phi with the x-axis, then theta - phi will be maximum when theta is equal to

The angle between the pair of straight lines y^2sin^2 theta-xy sin ^2 theta +x^2(cos ^2theta -1) =0 si

Range of f(theta)=cos^2theta(cos^2theta+1)+2sin^2theta is

If tan theta=a/b then b cos 2theta+asin 2theta=

If the chords through point theta and phi on the ellipse x^2/a^2 + y^2/b^2 = 1 . Intersect the major axes at (c,0).Then prove that tan theta/2 tan phi/2 = (c-a)/(c+a) .