The distance of a point on the ellipse `(x^2)/6+(y^2)/2=1` from the center is 2. Then the eccentric angle of the point is `pi/4` (b) `(3pi)/4` (c) `(5pi)/6` (d) `pi/6`

If (sqrt(3))b x+a y=2a b touches the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 , then the eccentric angle of the point of contact is pi/6 (b) pi/4 (c) pi/3 (d) pi/2

Find the eccentric angle of a point on the ellipse (x^2)/6+(y^2)/2=1 whose distance from the center of the ellipse is sqrt(5)

Find the eccentric angle of a point on the ellipse (x^2)/6+(y^2)/2=1 whose distance from the center of the ellipse is sqrt(5)

The equation of normal to the ellipse x^(2)+4y^(2)=9 at the point wherr ithe eccentric angle is pi//4 is

Find the equation of normal to the ellipse (x^(2))/(16)+(y^(2))/(9) = 1 at the point whose eccentric angle theta=(pi)/(6)

AB is a diameter of x^2 + 9y^2=25 . The eccentric angle of A is pi/6 . Then the eccentric angle of B is

The eccentric angle of a point on the ellipse (x^2)/4+(y^2)/3=1 at a distance of 5/4 units from the focus on the positive x-axis is cos^(-1)(3/4) (b) pi-cos^(-1)(3/4) pi+cos^(-1)(3/4) (d) none of these

If the tangent at the point P(theta) to the ellipse 16 x^2+11 y^2=256 is also a tangent to the circle x^2+y^2-2x=15 , then theta= (a) (2pi)/3 (b) (4pi)/3 (c) (5pi)/3 (d) pi/3

IF the lengths of the side of triangle are 3,5 and 7, then the largest angle of the triangle is pi/2 (b) (5pi)/6 (c) (2pi)/3 (d) (3pi)/4

The value of the integral int_0^oox/((1+x)(1+x^2))dx is (pi^)/2 (b) (pi^)/4 (c) (pi^)/6 (d) pi/3