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Equation of normal to parabola y^2 = 4ax...

Equation of normal to parabola `y^2 = 4ax` at `(at^2, 2at)` is `y-2at = -t(x-at^2) i.e. y=-tx+2at + at^3`
Greatest and least distances between two curves occur along their common normals. Least and greatest distances of a point from a curve occur along the normal to the curve passing through that point. Now answer the following questons: The point on the parabola `y^2 = 4x` which is nearest to the point (2, 1) is:
(A) `(1,2)` (B) `(1,2sqrt(2)` (C) `(1, -2)` (D) none of these

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