Equation of normal to parabola `y^2 = 4ax` at `(at^2, 2at)` is `

Find the equation of normal to the parabola y^2=4ax at point (at^2, 2at)

The equation to the normal to the parabola x^(2) = 2y at (1, 2) is

The equation to the normal to the parabola y^(2)=4x at (1,2) is

Find the equation of the normal to the parabola y^2 = 4ax such that the chord intercepted upon it by the curve subtends a right angle at the verted.

Find the equaton of normal to the parabola y^(2)= 4ax at the end of latusrectum in first quadrant

If the normal to the parabola y^2=4ax at the point (at^2, 2at) cuts the parabola again at (aT^2, 2aT) then

Find the equations of the tangent and normal to the parabola y^2=4a x at the point (a t^2,2a t) .

Find the equation of the tangent and normal to the parabola y^2=4a x at the point (a t^2,\ 2a t) .

Find the equation of tangent to the parabola y^(2)=8ax at (2a , 4a)

The normal to parabola y^(2) =4ax from the point (5a, -2a) are