Prove that the area in the first quadrant enclosed by the axis, the line `x=sqrt(3)y` and the circle `x^2+y^2=4\ i s\ pi//3.`

Find the area of the region in the first quadrant enclosed by x-axis, line x=sqrt(3)y and the circle x^2+y^2=4 .

Find the area of the region in the first quadrant enclosed by x-axis, the line y=sqrt(3\ )x and the circle x^2+y^2=16

Area of the region in the first quadrant exclosed by the X-axis, the line y=x and the circle x^(2)+y^(2)=32 is

Find the area of the region in the first quadrant enclosed by the y-axis, the line y=x and the circle x^2+y^2=32 , using integration.

Find the area of the region in the first quadrant enclosed by the x-axis, the line y" "=" x" , and the circle x^2+y^2=32 .

Area lying in the first quadrant and bounded by the circle x^(2)+y^(2)=4 the line x=sqrt(3)y and x-axis , is

Find the area enclosed by the curves y= sqrtx and x= -sqrty and the circle x^(2) + y^(2) =2 above the x-axis.

Find the area lying in the first quadrant and bounded by the curve y=x^3 and the line y=4xdot

Area lying in the first quadrant and bounded by the circle x^2+y^2=4 and the lines x= 0 and x= 2 is:

The radius of the larger circle lying in the first quadrant and touching the line 4x+3y-12=0 and the coordinate axes, is