The differential equation satisfying all the curves `y = ae^(2x) + be^(-3x)`, where a and b are arbitrary constants, is

Form the differential equation of family of curves y = ae^(2x) + be^(3x) , where a, b are arbitrary constants.

The differential equation of the family of curves y=e^(2x)(a cos x+b sin x) where, a and b are arbitrary constants, is given by

Find the differential equation of the family of curves y=A e^(2x)+B e^(-2x) , where A and B are arbitrary constants.

Find the differential equation of the family of curves y=A e^(2x)+B e^(-2x) , where A and B are arbitrary constants.

Find the differential equation of the family of curves y=A e^(2x)+B e^(-2x) , where A and B are arbitrary constants.

Find the differential equation of the family of curves y=A e^(2x)+B e^(-2x) , where A and B are arbitrary constants.

Find the differential equation representing the family of curves y=ae^(bx+5) , where a and b are arbitrary constants.

The differential equation satisfied by family of curves y = Ae ^(x)+Be ^(3x) + Ce^(5x) where A,B,C ar arbitrary constants is:

Obtain the differential equation of the curve y=a_(1) e^(x) + a_2 e^(-x) where , a_1 , a_2 being arbitrary constant.

The degree of the differential equation corresponding to the family of curves y=a(x+a)^(2) , where a is an arbitrary constant is