`(dy)/(dx)tany=sin(x+y)+sin(x-y)`

Solution of, (dy)/(dx)+sin[(x+y)/2]=sin[(x-y)/2] is: (A) ln|tany/2|+2sin(x/2)=c (B) ln|tan(y/4)|+2sin(x/2)=c (C) ln|tany/2|-2sin(x/2)=c (D) none of these

The general solution of the differential equation (dy)/(dx)+sin((x+y)/2)=sin((x-y)/2) is

The general solution of the differential equation (dy)/(dx)+sin((x+y)/2)=sin((x-y)/2) is

Solve (dy)/(dx)=cos(x+y)-sin(x+y) .

Statement-1: Solution of the differential equation tany *dy/dx =sin(x+y)+sin(x-y) is secy+2cosx=c .Statement-2: The differential equation tany *dy/dx =sin(x+y)+sin(x-y) is homogenous (A) Both 1 and 2 are true and 2 is the correct explanation of 1 (B) Both 1 and 2 are true and 2 is not correct explanation of 1 (C) 1 is true but 2 is false (D) 1 is false but 2 is true

dy/dx = sin(x-y)+cos(x-y)

If x sin(a+y)+sina.cos(a+y)=0 , then prove that (dy)/(dx) = (sin^(2)(a+y))/(sina)

Solve: (i) sin^(-1)((dy)/(dx))=x+y (ii) (dy)/(dx)=cos(x+y) (iii) (dy)/(dx)=(4x+y+1)^2

Solve (dy)/(dx)=(siny + x)/(sin2y-xcosy)

(dy)/(dx)=(x+sin x)/(y+cos y)