`(x^3+3x y^2)dx+(y^3+3x^2y)dy=0`

Show that the differential equation representing one parameter family of curves (x^2-y^2)=c(x^2+y^2)^2i s\ (x^3-3x y^2)dx=(y^3-3x^2y)dy

Solve: (x^3-3x y^2)dx=(y^3-3x^2y)dydot

Prove that x^2-y^2=c(x^2+y^2)^2 is the general solution of differential equation (x^3-3x""y^2)dx=(y^3-3x^2y)dy , where c is a parameter.

Solve each of the following initial value problem: x(x^2+3y^2)dx+y(y^2+3x^2)dy=0,\ y(1)=1

(x^2y^3+xy)dy=dx

Solve the following differential equations: (2x^2y+y^3^)dx+(x y^2-3x^3)dy=0

Solve the following differential equations: (x^2+3x y+y^2)dx-x^2dy=0

(2x^2+3y^2-7)x dx-(3x^2+2y^2-8)y dy=0

The solution of differential equation (2y+x y^3)dx+(x+x^2y^2)dy=0 is

solution of ( x+ y-1) dx + (2x+ 2y -3) dy=0 is :