Solve `ydx+(x-y^(2))dy=0`

Solve: y\ dx-(x+2y^2)dy=0

Solve ydx=(1+x^2)dy

Find the general solution of the differential equations (i) ydx+(x-y^(2))dy=0

Solve the equation ydx+(x-y^2)dy=0

Solve the equation ydx+(x-y^2)dy=0

Solve: y^(4)dx+2xy^(3)dy=(ydx-xdy)/(x^(3)y^(3))

The general solution of the differential equation ydx+(x+2y^(2))dy=0 is

Consider the differential equation ydx-(x+y^(2))dy=0 . If for y=1, x takes value 1, then value of x when y = 4, is

Solve the differential equation: y\ dx+(x-y^2)dy=0

Solve ydx-xdy=x^(2)ydx .