`dy/dx=x^3y^3-xy`

(dy)/(dx)=x^3y^3-x y

The solution of the equation dy/dx=x^3y^2+xy is (A) x^2y-2y+1=cye^(-x^2/2) (B) xy^2+2x-y=ce^(-y/2) (C) x^2y-2y+x=cxe^(-y/2) (D) none of these

xy-dy/dx=y^3e^(-x^2)

Find dy/dx if x^3=y^3

Solve: xy(dy)/(dx)=x^2-y^2

Find dy/dx if x^3+xy+y^3=40

Find dy/dx if x^2= 3xy

Solve : (dy)/(dx)=1-xy+y-x

Show that the differential equation 2xy (dy)/(dx) = x^2+3y^2 is homogeneousand solve it.

The solution of dy/dx+(1+y^3)/xy^2(1+x^2)=0