The normal lines to a given curve at each point pass through `(2,0)dot` The curve pass through `(2,3)` . Formulate the differntioal equation and hence find out the equation of the curve.

The slope of the tangent any point on a curve is lambda times the slope of the joining the point of contact to the origin. Formulate the differential equation and hence find the equation of the curve.

The normal to a given curve at each point (x ,y) on the curve passes through the point (3,0)dot If the curve contains the point (3,4), find its equation.

A curve passes through the point (0,1) and the gradient at (x,y) on it is y(xy-1) . The equation of the curve is

A curve passes through (1,pi/4) and at (x,y) its slope is (sin 2y)/(x+tan y). Find the equation to the curve.

Find the equation of the curve passing through origin and satisfying the differential equation 2xdy = (2x^(2) + x) dx .

A curve passes through the point (3, -4) and the slope of the tangent to the curve at any point (x, y) is (-x/y) .find the equation of the curve.

Find the equation of a curve passing through the point (0, 0) and whose differential equation is y^(prime)=e^ xsinx

If the curve satisfying differential equation xdy=(y+x^(3))dx passes through (1, 1), then the equation to the curve is

Find the equation of a curve passing through the point (0, 0) and whose differential equation is y^(prime)=e xsinx

Find the equation of the curve passing through the point (1, 1) whose differential equation is x dy =(2x^2+1)dx(x!=0) .