Show that the equation of the curve pass...

Show that the equation of the curve passing through the point `(1,0)` and satisfying the differential equation `(1+y^2)dx-xydy=0` is `x^2-y^2=1`

Similar Questions

Explore conceptually related problems

The equation of the curve through the point (1,0) which satisfies the differential equatoin (1+y^(2))dx-xydy=0 , is

The equation of the curve passing through the point (1,1) and satisfying the differential equation (dy)/(dx) = (x+2y-3)/(y-2x+1) is

The equation of the curve passing through the origin and satisfying the differential equation ((dy)/(dx))^(2)=(x-y)^(2) , is

Find the equation of the curve passing through the point (1,1) whose differential equation is : xdy=(2x^2+1)dxdot

The equation of curve passing through origin and satisfying the differential equation (1 + x^2)dy/dx + 2xy = 4x^2 , is

Find the equation of the curve passing through origin and satisfying the differential equation 2xdy = (2x^(2) + x) dx .

Find the equation of the curve passing through the point (1,1) whose differential equation is : xdy=(2x^2+1)dx

Find the equation of a curve passing through the point (0, 0) and whose differential equation is y^(prime)=e xsinx

Find the equation of the curve passing through the point (1, 1) whose differential equation is x dy =(2x^2+1)dx(x!=0) .

Find the equation of a curve passing through the point (0, 0) and whose differential equation is y^(prime)=e^ xsinx