`intdx/(x+sqrt(x-1))`

intdx/(xsqrt(x-1))

intdx/(x^2sqrt(x^2-1))

intdx/(xsqrt(1+x^n))

intdx/((x-1)sqrt(x^2-1))

Find intdx/((x-1)sqrt(x^2-1))

Evaluate: intdx/sqrt ((x-1)(x-2))

Evaluate: intdx/sqrt ((x-1)(2-x))

Evaluate : intdx/sqrt((x-1)(2-x)) by the substitution x=1+sin^2theta . Hence, find the value of int_1^2dx/sqrt((x-1)(2-x))

intdx/(sqrt(x)(1+x^2)^(5/4))= (A) (2x)/(1+x^2)^(1/4)+c (B) (2sqrt(x))/(1+x^2)^(1/4)+c (C) (2sqrt(x))/(1+x^2)+c (D) none of these

intdx/(sqrt(x+1)-root(4)(x+1))