`inte^(mtan^-1x)/(1+x^2)^2dx`

Similar Questions

Explore conceptually related problems

Evaluate inte^(mtan^-1x)/(1+x^2)^(3/2)dx

(i) int(1)/((1+x^(2))tan ^(-1) x )dx " "(ii) int(e^(tan^(-1)x))/(1+x^(2))dx

Evaluate: int(tan^-1x)^2/(1+x^2)dx

Evaluate: (i) int(sin(logx)/x\ dx (ii) int(e^mtan^((-1)x))/(1+x^2)\ dx

Evaluate: (i) int((1+logx)^2)/x\ dx (ii) int(sec^2(2tan^(-1)x))/(1+x^2)\ dx

Find (i) inte^x(t a n^(-1)x+1/(1+x^2))dx (ii) int((x^2+1)e^x)/((1+x)^2))dx

int(sin^(- 1)x)/((1-x^2)^(3/2))dx

If 2int_0^1 tan^(-1)x dx= int_0^1 cot^(-1)(1-x+x^2) dx then int_0^1 tan^(-1)(1-x+x^2) dx=

int(sin^(- 1)x)/((1-x^2)^(1/2)) dx

(i) int(tan^(-1))/((1+x^(2)))dx" "(ii) int(1)/(sqrt(1-x^(2)) sin^(-1)x)dx