`int ((f (x) g' (x) -f' (x) g (x))/(f (x) g(x)))(log (g(x )) - log (f(x)))dx `is equal to:

int (f'(x))/( f(x) log(f(x)))dx is equal to

int \ {f(x)*g^(prime)(x)-f^(prime)(x)g(x))/(f(x)*g(x)){logg(x)-logf(x)} \ dx

Evaluate: int[f(x)g''(x)-f''(x)g(x)]dx

Let g (x) be then inverse of f (x) such that f '(x) =(1)/(1+ x ^(5)), then (d^(2) (g (x)))/(dx ^(2)) is equal to:

Let g (x) be then inverse of f (x) such that f '(x) =(1)/(1+ x ^(5)), then (d^(2) (g (x)))/(dx ^(2)) is equal to:

The value of int [f(x)g''(x) - f''(x)g(x)] dx is equal to

If f(x) = 3x + 1 and g(x) = x^(2) - 1 , then (f + g) (x) is equal to

If f(x) = 7x + 9 and g(x) = 7x^(2) - 3 , then (f - g)(x) is equal to

If f(x)=|x-1|" and "g(x)=f(f(f(x))) , then for xgt2,g'(x) is equal to

If f(1) =g(1)=2 , then lim_(xrarr1) (f(1)g(x)-f(x)g(1)-f(1)+g(1))/(f(x)-g(x)) is equal to