`intx^2/(xsinx+cosx)^2dx=-(xsecx)/(xsinx+cosx)+f(x)+c`, then `f(x)` may be (A) `sinx` (B) `xsinx` (C) `tanx` (D) `cotx`

Evaluate: int(x^2+6)/(xsinx+3cosx)^2dx

Evaluate: int(x^2+42)/(xsinx+7cosx)^2dx

Evaluate: int(x^2)/((xsinx+cosx)^2)\ \ dx

Evaluate: int_0^(pi//2)(xsinx cos\ x)/(sin^4x+cos^4x)dx

If intsqrt(1+sinx)f(x)dx=2/3(1+sinx)^(3/2)+c ,t h e nf(x)e q u a l cosx (b) sinx (c) tanx (d) 1

Evaluate: inte^(xsinx+cosx){(x^4cos^3x-xsinx+cosx)/(x^2cos^2x)}dx

Evaluate : int(x^2+20)/((xsinx+5cosx)^2)dx

Evaluate : int(xcosx)/((xsinx+cosx)^(2))dx .

int(dx)/(sin^2xcos^2x) equals(A) tanx+cotx+C (B) tanx-cotx+C (C) tanxcotx+C (D) tanx-cot2x+C

intx^(sinx) ((sinx)/x+cosxdotlogx) dx is equal to (A) x^(sinx)+C (B) x^(sinx)cosx+C (C) ((x^(sinx))^2)/2+C (D) none of these