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If mgt0, ngt0, the definite integral I=i...

If `mgt0, ngt0`, the definite integral `I=int_0^1 x^(m-1)(1-x)^(n-1)dx` depends upon the values of `m` and `n` is denoted by `beta(m,n)`, called the beta function.Obviously, `beta(n,m)=beta(m,n)`.Now answer the question:If `int_0^2 (8-x^3)^((-1)/3)dx=kbeta(1/3,2/3)`, then `k` equals to (A) `1` (B) `1/2` (C) `1/3` (D) `1/4`

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