Show that the ratio of the areas into which the circle `x^2+y^2 = 64a^2` is divided by the curve `y^2=12x` is `(4pi+sqrt(3))`.

The area common to the circle x^2 + y^2 = 64 and the parabola y^2 = 12x is equal to

The figure into which the curve y^2 = 6x divides the circle x^2 + y^2 = 16 are in the ratio

One of the diameters of the circle x^2+y^2-12x+4y+6=0 is given by

Find the ratio in which the area bounded by the curves y^2=12 x and x^2=12 y is divided by the line x=3.

Find the ratio of the areas of two regions of the curve C_(1) -= 4x^(2) + pi^(2)y^(2) = 4pi^(2) divided by the curve C_(2) -= y = -(sgn(x - (pi)/(2)))cos x (where sgn (x) = signum (x)).

Show that the angle between the circles x^2+y^2=a^2, x^2+y^2=ax+ay is (3pi)/4

the area between the curves y= x^2 and y =4x is

The area enclosed by the curve y^2 +x^4=x^2 is

The ratio of the areas of two regions of the curve C_(1)-=4x^(2)+pi^(2)y^(2)=4pi^(2) divided by the curve C_(2)-=y=-(sgn(x-(pi)/(2)))cosx (where sgn (x) = signum (x)) is

Find the ratio in which the line joining the points (6, 12) and (4, 9) is divided by the curve x^(2)+y^(2)=4 .